Use the discriminators to determine the number of solutions for the quadratic equation.
y=3x^2+7x+6
show work

no real solutions

Step-by-step explanation:

For a quadratic in standard form : y = ax² + bx + c : a ≠ 0

The value of the discriminant

Δ = b² - 4ac informs about the nature of the solutions

• If b² - 4ac > 0 then 2 real and distinct solutions

• If b² - 4ac = 0 then 2 real equal solutions

• If b² - 4ac < 0 then no real solutions

For y = 3x² + 7x + 6

with a = 3, b = 7, c = 6, then

b² - 4ac = 7² - (4 × 3 × 6) = 49 - 72 = - 23

Since b² - 4ac < 0 the equation has no real solutions

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

all it means is function 3