Need to find the zeros for this quadratic equation

see explanation

Step-by-step explanation:

Given

y = x² + 2x + 1

To find the zeros let y = 0, that is

x² + 2x + 1 = 0 ← x² + 2x + 1 is a perfect square

(x + 1)² = 0

x + 1 = 0 ( subtract 1 from both sides )

x = - 1 with multiplicity 2 ← zero

This indicates that the graph has a minimum turning point at (- 1, 0)

Note from your table

the value for x = - 1 should be y = 0 ( not - 2 )

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

step-by-step explan mxfcg'k; uafwgzfgjhklhgation: