Figure 1 is a square pyramid. figure 2 is a right triangular prism.

complete the following statement about figures 1 and 2.

the surface area of figure 1 is square centimeters than the surface area of figure 2.

the answer is

The surface area of Figure 1 is 10.2 square centimeters Less than the surface area of Figure 2.

Step-by-step explanation:

Figure 1

area of a square = s2

=9squared

=81 sq cm

area of triangle = 1/2 bh

=1/2 (9cm) (14cm)

=63 sq. cm

find surface area

SA = 81 sq. cm + 4(63 sq. cm)

SA = 81 sq. cm + 252 sq. cm

SA = 333 sq. cm

Figure 2 Calculation

area of rectangle = lw

a = (12cm) (8 cm)

a = 96 sq. cm

area of triangle = 1/2 bh

=1/2 (8 cm) (6.9 cm)

= 27.6 sq. cm

total surface are of figure 2

SA = 3 (96 sq.cm) + 2 (27.6 sq. cm)

SA = 288 sq. cm + 55.2 sq. cm

SA = 343.2 sq. cm

find the difference between figure 1 and figure 2

343.2 sq. cm - 333 sq. cm = 10.2 sq. cm

depending on others is critical to survival. my source is apex!

step-by-step explanation:

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq