What is the reciprocal of tanb in the triangle below?

Step-by-step explanation:

Note that the reciprocal of tan B is by definition the cotangent (cot) of B:

   1                        adjacent side           BC

= cot B = =  

 tan B                   opposite side            AC

Hence, The reciprocal of tan B is tan A

B is correct.

Step-by-step explanation:

We are given a right angle triangle. Right angle at ∠C

We need to find the reciprocal of tan B

First we write the formula of tan B using trigonometry identity.

In ΔABC, ∠C=90°

Now we reciprocal it.

Comparing both equation ( Right sides equal )

Hence, The reciprocal of tan B is tan A.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the answer is 8/21

hope this