Can someone me with this? and explain your work.

Part A: y = 3 inches

Part B: Area = 60 square inches

Step-by-step explanation:

perimeter of the rectangle = 34 inches =2*(4y)+2*x

2*(4y)+2*x =34 Equation 1

perimeter of the triangle = 40 inches =5y +5y +2x

5y +5y +2x = 40 Equation 2

Using Equation 2 we have:

10y+2x = 40

2x= 40-10y

x= (40-10y)/2

We have:

x= 20-5y  Equation 3

Using Equation 1

2*(4y)+2*(20-5y) =34

8y+40-10y =34

40-34=2y

6=2y   so we have y=3inches

Area of the rectangle=x*4y= 5*4*(3)=60 square inches

Using  x= 20-5y  Equation 3

X=20-5*3=5

answer: 4 (:

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4