How do you solve 3x+1 = 15 for x using the change of base formula log base b of y equals log y over log b?

Answer with explanation:

The given equation in single variable x, is

⇒3 x+1=15

Subtracting 1 from both sides

⇒ 3 x +1 -1 = 15- 1

⇒3 x =14

Dividing both sides by, 3 we get

Because ,log 10=1

it's

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