The point (-3, 7) is on the terminal side of angle θ, in standard position. what are the values of sine, cosine, and tangent of θ?

i need an answer !

sinθ = 0.9191; cosθ = -0.3939; tanθ = -2.333

Step-by-step explanation:

The point (-3, 7) is in the second quadrant, so θ is an obtuse angle as in the figure below.

AB = 7

OA = -3

According to Pythagoras,

OB² = OA² + AB² = (-3)² + 7² = 9 + 49 = 58

OB = √58 = 7.616

sinθ = 0.9191; cosθ = -0.3939; tanθ = -2.333

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12