Mathematics, 22.09.2019 04:30 emwvoidsnake
Zeke deposited $300 into a savings account. the interest rate on the account is 3%, compounded continuously. to determine how long it will take to triple his money, zeke wrote the following equation, where t represents time, in years.
900=300e^0.03t
which equation is equivalent to the one zeke wrote?
ln900=ln(9t)
ln900=9t
ln3=0.03t
ln3=ln(0.03t)
Answers: 2
![\bf \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\textit{let's use this one}}{log_a a^x = x}\qquad \quad a^{log_a x}=x \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 900=300e^{0.03t}\implies \log_e(900)=\log_e(300e^{0.03t})](/tpl/images/0251/1874/2e2cf.png)
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Zeke deposited $300 into a savings account. the interest rate on the account is 3%, compounded conti...
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