Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form?

6x3 + 4x2 − 6x − 4 = 2(x + k)(x − k)(3x + 2)

k=

k=1

Step-by-step explanation:

6x³ + 4x² − 6x − 4 = 2(x + k)(x − k)(3x + 2)

In 6x³ + 4x² − 6x − 4   we have common factor 2.

So,

6x³ + 4x² − 6x − 4 = 2(3x³+2x²-3x-2)

(3x³+2x²-3x-2)=(x + k)(x − k)(3x + 2)

(x + k)(x − k) = (3x³+2x²-3x-2)/(3x+2)

(x + k)(x − k) = x²-1

(x + k)(x − k) =(x+1)(x-1)

So, k=1

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i believe the answer is 323 ft

step-by-step explanation: