8. (x - 5) + (y - 11)^2= 81
a) find its center
b) its radius
c) one point on the circle

Step-by-step explanation:

The equation of a circle in standard form:

(h, k) - center

r - radius

We have the equation:

Therefore

a) h = 5, k = 11 → the center (5, 11)

b) r² = 81 → r = √81 = 9 - radius

c) We choose any value of x, but one which h - r ≤ x ≤ h + r

5 - 9 = -4

5 + 9 = 14

-4 ≤ x ≤ 14

Let x = -4. Put to the equation and solve for y:

          subtract 81 from both sides

        add 11 to both sides

(-4, 11)

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