Anyone can you explain?

a goblet contains 3 red balls, 2 green balls, and 6 blue balls.

if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

9/55

P(1st = red and 2nd = blue)

= (3/11) x (6/10)

= 18/110

= 9/55

To find the probability of something happening,

= (number of desired outcomes) / (total number of outcomes)

If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together