Ineed this asap

click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. release your mouse button when the item is place. if you change your mind, drag the item to the trashcan. click the trashcan to clear all your answers.
find the total area the regular pyramid.

54√3 +18√91 units²

Step-by-step explanation:

The regular hexagon base is comprised of 6 equilateral triangles, each having a side length of 6. That means the internal right triangle shown having a face edge as its hypotenuse has side lengths of 6 and 8. The face edge length is then ...

   face edge = √(6² +8²) = 10 . . . . . double the hypotenuse of a 3-4-5 right triangle, as expected

So, each of the 6 base triangles is an equilateral triangle with side length 6, and each of the 6 face triangles is an isosceles triangle with side lengths 10 and base length 6.

In each case, the altitude of the triangle can be figured from the Pythagorean theorem:

  face slant height = √(10² -3²) = √91

  base apothem = √(6² -3²) = 3√3

The area of each of these triangle is half the product of its base width and height. The total area of the pyramid is 6 times the sum of the areas of these two triangles.

  total surface area = 6·(1/2·6·√91 +1/2·6·3√3) = 18(√91 +3√3)

  total surface area = 18√91 +54√3 . . . units²

answer: 180

step-by-step explanation:

12-2=10

20-2=18

18x10=180

answer:

sometimes

*i think