How i can factor to solve the equation

2x^3+3x^2-11x-6=0

(x-3)(2x^2+3x-2)=0

(x-3)((2x-1)(x+2))=0

(x-3)(2x-1)(x+2)=0

x=3,1/2,-2

Use my steps to answer remember for a question like that use

( 2x³ +3x²)-( 11x-6 )= 0

Step-by-step explanation:

So far you have solved linear equations, which include constant terms—plain numbers—and terms with the variable raised to the first power,  

x1=xx^1=xx  1 =5 x

, start superscript, 1, end superscript, equals, x

You may have also solved some quadratic equations, which include the variable raised to the second power, by taking the square root from both sides.

Here is example

(x−1)    x−1=0  x=1  (x+3)=0  x+3=0 x=−3

Substituting either  x=1x=1 x=1 x, equals, 1  or  x=−3x=-3 x=−3 x, equals, minus, 3  into the equation will result in the true statement  0=00=0 0=0 0, equals, 0 , so they are both solutions to the equation.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: