What is the equation in point slope form of the line passing through (3,6) and (-2,1)

Step-by-step explanation:

note :

The equation of a linear function in point-slope form is y – y1 = m(x – x1)

The point is A (x1 , y1)

m : the slope

the slope is : m =   (YB - YA)/(XB -XA) A(3;6)   B(-2;1)

m =(1-6)/(-2-3)  = -5/(5)  =  1

the equation in point slope form of the line passing through (3,6) and (-2,1)is:

y - 6 = 1(x-3)

£56

step-by-step explanation:

c) yes, because of asa or aas