Me plz asap

two clocks are circular. clock a has twice the area as clock b. how many times greater is the radius of clock a than the clock b radius

The radius of clock A is √2 greater than the radius of clock B

The radius of clock A is 1.41 greater than the radius of clock B

Step-by-step explanation:

* Lets talk about the similar circles

- All the circles are similar because all the circles have the same

 measure 360° and there is a ratio between their radii

- If the ratio between the radii of two circles is a/b, then the ratio

 between their circumferences is also a/b

- If the ratio between the radii of two circles is a/b, then the ratio

 between their areas is (a/b)²

* Now lets solve the question

- Clock A has area twice the area as clock B

∴ Area of circle A = 2 Area of circle B

- If the ratio between their radii is a/b

∵ Area of circle A /area of circle B = 2

∴ (a/b)² = 2 ⇒ take a square root for both sides

∴ a/b = √2

∴ The radius of clock A is √2 greater than the radius of clock B

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!