Square abcd is located on a coordinate plane. the coordinates for three of the vertices are listed below.
a (2,7) , c (8,1),d (2,1)
square abcd is dilated by a scale factor of 2 with the center of dilation at the origin, to form square a’b’c’d’. what are the coordinates if vertex b’?

ANSWER

B' has coordinates (16,14).

EXPLANATION

The given coordinates of square ABCD are :

A (2,7) , C (8,1),D (2,1)

In order to form a square, the coordinates of B should be: (8,7)

The mapping for dilation with a scale factor 2, about the origin is

This implies that:

When we simplify we get:

Hence B' has coordinates (16,14).

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!