The straight line p has the equation y= 2x-5
find an equation of the straight line perpendicular to p which passes through (-2,3)
asap

y=−x/2+2.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=2x−5.

The slope of the perpendicular line is negative inverse: m=−12.

So, the equation of the perpendicular line is y=−x/2+a.

To find a, we use the fact that the line should pass through the given point: 3=(−12)⋅(−2)+a.

Thus, a=2.

Therefore, the equation of the line is y=−x/2+2.

idk

step-by-step explanation: