Law of cosines: a2 = b2 + c2 – 2bccos(a) what is the measure of n to the nearest whole degree? 35° 45° 55° 65° the triangle sides are 7 4 5.74

option C

N ≈ 55°

Step-by-step explanation:

Given in the question a right angle triangle.

To calculate the angle N, we will use following formula

a² = b² + c² -2bcCos(A)

here,

a = 5.74

b = 4

c = 7

A = N°

Plug values in the formula

5.74² = 4² + 7² -2(4)(7)COS(N)

32.95 = 16 + 49 - 56COS(N)

32.95 = 65 - 56COS(N)

32.95 - 65 = - 56COS(N)

-32.05 = - 56COS(N)

minus will cancel out

32.05 =  56COS(N)

COS(N) = 32.05/56

COS(N) = 0.57

N = (0.57)

N = 55.08°

N ≈ 55°

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4