Find the next four terms in the arithmetic sequence.

a - 6, a - 2, a + 2,

a.

a + 6, a + 12, a + 15, a + 18

c.

a + 6, a + 10, a + 14, a + 18

b.

a + 4, a + 10, a + 12, a + 14

d.

a + 4, a + 6, a + 8, a + 10

select the best answer from the choices provided

a

b

c

d

can anyone explain this.

i can't find the final answer

pls

c

Step-by-step explanation:

Since the sequence is arithmetic then there is a common difference d between consecutive terms.

d = -

  = a - 2 - (a - 6) = a - 2 - a + 6 = 4

Hence the next 4 terms are

a + 2 + 4 = a + 6

a + 6 + 4 = a + 10

a + 10 + 4 = a + 14

a + 14 + 4 = a + 18

That is

a + 6, a+ 10, a + 14, a + 18 → c

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18