Answers: 3
![\displaystyle \frac{d}{dx}[x\sqrt{x}-x^{2}\sqrt{x}]](/tpl/images/0441/2063/22476.png)
is the same as 
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?![\displaystyle \frac{d}{dx} [x^{3/2}] = \underbrace{3/2}_{\begin{aligned}&\text{from}\\[-0.5em]& \text{power}\end{aligned}} \;x^{(3/2) - 1} = \frac{3}{2}\;x^{1/2}](/tpl/images/0441/2063/99e0d.png)
.![\displaystyle \frac{d}{dx} [x^{5/2}] = \underbrace{5/2}_{\begin{aligned}&\text{from}\\[-0.5em]& \text{power}\end{aligned}} \;x^{(5/2) - 1} = \frac{5}{2}\;x^{3/2}](/tpl/images/0441/2063/e708c.png)
.![\displaystyle\begin{aligned} \frac{d}{dx}[x\sqrt{x}-x^{2}\sqrt{x}] &=\frac{d}{dx}[x\sqrt{x}] - \frac{d}{dx}[x^{2}\sqrt{x}] \\&=\frac{3}{2}\;x^{1/2} - \frac{5}{2}\;x^{3/2}\\ &=\frac{3}{2} \sqrt{x} - \frac{5}{2} x\sqrt{x}\end{aligned}](/tpl/images/0441/2063/62347.png)
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