1.
john weighs three times as much as karen. two times john’s weight plus karen’s weight is 875 pounds. how much does john weigh? how much does karen weigh?
(hint: let j stand for john’s weight, and let k stand for karen’s weight.)

2.
mary is three times as old as joe. mary’s age plus joe’s age is 24. find mary’s age and joe’s age. (hint: let m stand for mary’s age, and let j stand for joe’s age.)

will mark as brainlest

1 answer

weight of karen = k

weight of john = j

by the question

j=3k

then

case II

2j +k =875

2×3k+k=875

7k = 875

k=875/7

k=125

now

j=3k

=3×125

=375

hence john was 375 pound and karen was 125.

2 answer

let Mary be m and joes be j

by question

M=3J

CASE II

M + J=24

3J +J =24

J =24/4

J=6

NOW

M=3×6

M=18

Therefore Mary was 18 yrs old and Joes was 6 yrs old.

Answer 1...

j =3k

2j + k = 875

substituting the first eqn into the 2nd

2(3k) + k = 875

6k+ k =875

7k = 875

k =875/7 =125

thus j = 3(125) =375

Answer...2

m =3j

m+j = 24

3j +j= 24

4j= 24

joe= 6yrs

mary= 3(6) =18yrs

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.