Can anybody me on this
16
16π
16π - 16
16 - 16π
are the answer choices

The area of the white region = 16π - 16 ⇒ third answer

Step-by-step explanation:

* Look at the figure and lets explain it

- A circle with two diameters perpendicular to each other

- Two shaded isosceles right angled triangle with leg length 4 units

* To find the area of the white region:

- Find the area of the circle ⇒ (1)

- Find the area of the two shaded triangles ⇒ (2)

- Subtract (2) from (1)

* Lets do that

∵ The length of the radius of the circle = 4 units

∴ The area of the circle = π (4)² = 16π

∵ The area of each triangle = (1/2) × base × height

∵ The length of the base and the length of the height = 4 units

∴ The area of the two triangles = 2 × 1/2 × 4 × 4 = 16 units

* Lets subtract the area of the triangles from the area of the circle

∴ The area of the white region = 16π - 16

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: