(i'm so lost i need with this ! )
the area of a square is calculated with the formula a = s^2, where s is the length of one side of the square.

given that the area of the square shown below is 25cm^2.

answer the following questions:

1. what is the length of any side of the square?

2. what is the length of the diagonal of the square (labeled x in the figure below)? hint: substitute the side length you just found in the pythagorean theorem a^2 + b^2 = c^2.

(be sure to show all your work in complete sentences! )

The side length is 5 cm

The diagonal is 5 sqrt(2) cm

Step-by-step explanation:

A = s^2

We know the area is 25

25 = s^2

Take the square root of each side

sqrt(25)= sqrt(s^2)

5 =s

The side length is 5 cm

2  We use the Pythagorean theorem a^2 + b^2 = c^2.  to find the diagonal

a^2 + b^2 = c^2

5^2 + 5^2 = c^2

25+25 = c^2

50 = c^2

Take the square root of each side.

sqrt(50) = sqrt(c^2)

sqrt(25*2) = sqrt(c^2)

sqrt(25) sqrt(2) = c

5sqrt(2) =c

The diagonal is 5 sqrt(2)

google dat sis

step-by-step explanation:

the diameter is 16 cm. are you a teacher?

step-by-step explanation: