The function f(x) = –(x – 3)2 + 9 can be used to represent the area of a rectangle with a perimeter of 12 units, as a function of the length of the rectangle, x. what is the maximum area of the rectangle?

Step-by-step explanation:

f(x) = –(x – 3)2 + 9

      = 3² - (x – 3)2  identity a²-b² = (a+b)(a - b)  where : a =3 and b = x-3

     = ( 3+x-3) (3-x+3)

    f(x) = x( 6-x)

the perimeter is ; 2(x +6-x) =12

the maximum area of the rectangle is : f(3) = 9 m²

The maximum area of rectangle is:

                   9 square units

The function f(x) is given by:

where f(x) represent the area of rectangle.

Also, the area is maximized at the value of x where the derivative is equal to zero.

Hence,

Hence, when x=3 the area of the rectangle is maximum.

Also, the maximum area of rectangle is:

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers