Suraj took a slice of pizza from the freezer and put it in the oven. the pizza was heated at a constant rate.
the table compares the pizza's temperature (in degrees celsius) and the time since suraj started heating it (in minutes).
time (minutes) temperature (degrees celsius)
111 2.52.52, point, 5
777 47.547.547, point, 5
131313 92.592.592, point, 5
how fast was the pizza heated?

degrees celsius per minute

The pizza heats up an average of 7.50 degrees per minute

Step-by-step explanation:

The table shown

Time (minutes)Temperature (degrees Celsius)

1                          2.52

7                          47.547

13                          92.592

Since the pizza was heated at a constant rate, we can model the experiment as a line, where the slope represents how fast the pizza was heated

Slope

m   =  (y2 - y1)/(x2 - x1)

Let

(x1,y1) = (7, 47.547)

(x2,y2) = (13, 92.592)

m = (92.592 - 47.547)/(13-7)

m = 7.5075

The pizza heats up an average of 7.50 degrees per minute

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.