What is the equation of a line perpendicular to the line with the equation 3x + 4y = 7

Any line where m = 4/3 in y=mx + b such as y = 4/3x

Step-by-step explanation:

Perpendicular lines are lines which slopes are negative reciprocals. The slope of the line 3x + 4y = 7 is found by converting it to y = mx + b. It becomes y = -3/4x + 7/4. The slope is m = -3/4. A line perpendicular to this line will have a slope of m = 4/3 such as the line y = 4/3x.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752