find the least common multiple for a2b2 and a3bc.

a) a3b2c

b) c

c) a2b2

d) a2b2c

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

168

step-by-step explanation:

i am pretty sure that the answer is 168

9987

step-by-step explanation: