Solve the system of equations y=-2x y=x2-8

Step-by-step explanation:

Make both equations equal to each other and solve for x:

Factor the quadratic equation. You need to find two number that when you add them you get 2 and when you multiply them you get -8.

These numbers are 4 and -2. Then:

Substitute the values of x calculated, into any of the original equations. Then:

For this case we must solve the following system of equations:

Matching we have:

The solution will be given by:

Substituting:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐