If lmno is a rectangle, and mo = 36, what is the length of np

Solution:

L M NO, is a rectangle , in which , MO=3 6 unit

LN and MO intersect each other at P.

⇒Diagonals of rectangle are equal as well as, Diagonals of rectangle bisect each other.

LN=MO

Also, MP=OP and LP=NP.

→MP +OP=MO

→OP +OP=36

→2 OP=36

Dividing both sides by ,2 we get

O P =18 unit

→MP=OP=18 unit

→ LP=NP=1 8 unit

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

20%

step-by-step explanation: