Aright rectangular prism has a langht of 5cm, a with of 4 cm, and a hight of 3 cm. the dimensions of the prism are doubled. what is the surface area of the enlarged prism?

Given

Dimentions of the rectangular prism are

Step-by-step explanation:l=5cm, b=4cm, h=3cm

If each dimension is doubled then new prism dimensions are

L=10cm, B=8cm, H=6cm

Therefore Required surface area

Total surface area(TSA) =2(LB+BH+LH)

=2[10×8+8×6+10×6]

=2(80+48+60)

=2×188

=376square cm

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;