10 points & brainliest - what are the coordinates of vertex j of the pre-image?

ANSWER

(0,-4)

EXPLANATION

The coordinates of J' are (0,-2).

Let the coordinates of J be (a,b).

Then we apply the rule of the dilation to get,

.

This implies that,

And also,

Hence the vertex J of the preimage is

(0,-4)

The first choice is correct.

(0, -4)

Step-by-step explanation:

A dilation rule of means that the coordinates of each point in the pre-image must be divided by 2.

So, we must multiply the coordinates of each point in the image by 2 to get back to the pre-image.

The coordinates of vertex J' are (0, -2), so those of J must have been (0, -4).

Vertex J moved to the origin along the ray until its coordinates were halved.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47