Which logarithmic equation is equivalent to 2^5=32

5=log_{2}(32)5=log

2

(32)

Step-by-step explanation:

1. By definition, you have if y=b^{x}y=b

x

, then x=log_{b}(y)x=log

b

(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

2^{5}=322

5

=32

Where:

\begin{lgathered}x=5\\y=32\\b=2\end{lgathered}

x=5

y=32

b=2

- Substitute values into x=log_{b}(y)x=log

b

(y) . Then, you obtain:

5=log_{2}(32)5=log

2

(32)