How do you graph these systems of equations y=6x-3 and y=-1/6x+7

See the figure.

Step-by-step explanation:

The Slope-intercept form of the equation of the line is:

Where:

m: the slope

b: the intersection of the line with the y-axis.

Both equations in the system of equations has this form, therefore, you can know that:

Has:

Has:

You can find the intersection with the x-axis by substituting y=0 and solving for x:

For the line :

For the line :

Therefore, knowing the intersection of each line with the y-axis and the intesrection with the x-axis, you can graph both lines, obtaining the graph shown attached.

The point of intersection of this lines is the solution of the system of equations, as you can observe in the graph.Therefore:

hreryryrranswer:

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204