Mathematics, 06.10.2019 00:40 shardaeheyward139
The equation of a parabola is (y−3)2=20(x+1) . what is the equation of the directrix of the parabola? enter your answer in the box.
the equation . not the answer.
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (y-3)^2=20(x+1)\implies [y-\stackrel{k}{3}]^2=4(\stackrel{p}{5})[x-(\stackrel{h}{-1})]~\hfill \begin{cases} \stackrel{vertex}{(-1,3)}\\ p=5 \end{cases}](/tpl/images/0291/4662/e6d71.png)
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The equation of a parabola is (y−3)2=20(x+1) . what is the equation of the directrix of the parabola...
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