Which is the equation of a line that has a slope of -2/3 and passes through point (–3, –1)?

y = (-2/3)x-3

Step-by-step explanation:

Hello:

equation is the line is : y = ax+b        a is a slope

y = (-2/3)x+b

passing through the point (−3;−1) :   -1 =(-2/3)(-3)+b    so : b = -3

y = (-2/3)x-3

second solution : you can verify (-3 ; -1) in the equation : y = (-2/3)x-3

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value