If the equation of the regression line for the data set (3,6), 6,8), (9,4) is y=-1/3x+8, what is the sse for the data set? a. 4 b. 1 c. 8 d. 6

D. 6

Step-by-step explanation:

⇒The question is on Sum of Squared Errors(SSE)

⇒A linear regression equation is one inform of Y= a +bx where Y is dependent variable and x is the independent variable where as b is the slope.

⇒SSE for a set of data is the sum of squares of the calculated residuals where a residual/error is a deviation of a point from that in the line of best fit.

⇒General expression; y₁-y₀ where y₁ is the point out of the line and y₀ is the point in the line of best fit.

⇒ y₁-y₀ =ε₀................where  ε is epsilon

⇒sum= (ε₀)² + (ε₁)² + (ε₂)²

ε₀= a (3,6).......A (3,7)......(6-7)² = -1² = 1

ε₁= b (6,8).......B (6,6).......(8-6)²= 2²= 4

ε₂= c (9,4).......C (9,5).......(4-5)²= -1² = 1

Sum of squares is = 1+4+1= 6

See attached graph showing the points on the line and those out of the line.

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35