Solve for x. enter your answer in interval notation using grouping symbols. x^2 + 5x < -4

interval notation (-4,-1)

Step-by-step explanation:

x^2+5x<-4

bring "-4" to the left side

x^2+5x+4=0

*switch to "=" sign here to solve this using the quadratic formula

-b+- sqrt b^2-4ac/2a

substitute the values in the quad formula with the values in your inequality

−4<x<−1

convert this to interval notation by using the number at the beginning and end of the inequality

(-4,-1)

hope this helps, plz vote my ans the brainiest!

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

black lol

step-by-step explanation:

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tommy has 2.

this made me lol.