In the equation, t is a constant. if the equation has no real solutions, what could be the value of t? 2x^2 − 4x = t im struggling and my teacher doesnt teach me anything sooo

t>-2

Step-by-step explanation:

Given a quadratic equation ax²+bx+c = 0, the solutions to the equal can either be real or no real solution (complex).

For the equation to have a complex solution, the discriminant given as D = b²-4ac must be greater than zero i.e

b²-4ac > 0

Given the quadratic equation:

2x² − 4x = t

It can also be written as:

2x²-4x-t = 0

Where a = 2, b = -4 and c= -t

For the equation to have no real solution, b²-4ac > 0

(-4)² - 4(2)(-t) > 0

16+8t >. 0

16 > -8t

Dividing both sides by -8:

16/-8 < -8t/-8 (the sign change is because we divide both sides of the inequality by a negative value)

-2<t OR t>-2

The value of t will be greater than -2

0 is its x and y coordinate