Can anyone tell me why i’m not getting full marks (3/4) marks.

£59.25

Step-by-step explanation:

i will put my full working then you will be able to spot where you went wrong

formula :

1/2 * ( sumof parallel sides ) * height

= 1/2 * (12 +20 )* h

since height is not given we need to use Pythagoras theorem

right angle triangle

c^2 = a^2 + b^2

17^2 = a^2 + (20-12 )^2

17^2 = a^2+ 8^2

a^2 = 17^2 - 8^2

a^2 = 225

a = 15

height = 15 cm

trapezium area , include the height amount:

1/2 * ( 12 + 20 )* 15

=240 m^2

since 1 can can cover 100 m^2

we can use cross multiplication to find out the amount of cans used :

1          :             100

x         :              240

240 = 100x

x = 240/100

x = 2.4

rounded off is 3 cans

hence we need 3 cans

3 * 19.75

hence the only issue you had was putting 2.4 cans. you can not buy 2.4 cans but only 3 cans.

hence you will have to multiple 19.75 * 3 = 59.25 . that was your error

if x decreases by 4 then y increases by 10

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.