Arectangle has a length of 8 feet and a width of 6 feet if its length and width in creased by 50% each what is the area of the new rectangle

108 ft^2

Step-by-step explanation:

New Length: 8 * 1.5 = 12

New width: 6 * 1.5 = 9

New area = 12 * 9 = 108 ft^2

Hello there!

108 ft²

Step-by-step explanation:

In this question, we are trying to find the new area of a rectangle in which the sides are increased by 50%.

First thing we must do is find the new size of the side lengths (8 and 6).

We will find a 50% increase in 8, and 50% increase in 6.

We would multiply the numbers by 0.5.

8 × 0.5 = 4

6 × 0.5 = 3

Then, we would add those numbers to the side lengths that it belongs to.

8 + 4 = 12

6 + 3 = 9

The increased side lengths would be 12 (length and 9 (width)

To find the area, you would multiply length × height.

12 × 9 = 108

The area of the new rectangle would be 108 ft²

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

ur right ive taken the test

step-by-step explanation: