Angle a is in standard position and terminates in quadrant iv. if sec(a) = 4 3 , complete the steps to find cot(a). use the identity (choices are sin^2(a) + cos^2(a) = 1, tan^2(a) + 1 = sec^2(a), 1 + cot^2(a) = csc^2(a) ) to find the value of ).

tan²A +1 = sec²A; cotA = -(3√7/7); A = 311.41°

Step-by-step explanation:

secA = 4/3

sec²A = 16/9  

Use the identity tan²A +1 = sec²A

tan²A = sec²A - 1 = 16/9 - 1 = 7/9

cot²A = 1/tan²A = 9/7

We are in the fourth quadrant, so the cotangent is negative.

cotA = -√(9/7) = -3/√7 = -(3√7/7)

tan A = 1/cotA = -√7/3

A = -48.59° = 311.41°

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

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