The length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 44 yd^2 find the dimensions of the rectangle.

width: 5.5 yd; length: 8 yd

Step-by-step explanation:

Let w represent the width of the rectangle in yards. Then 2w-3 is the length and the area is the product of length and width:

w(2w-3) = 44

2w^2 -3w -44 = 0 . . . . put the equation into standard form

(w+4)(2w -11) = 0 . . . . . factor the equation

w = -4 or 11/2 . . . . . . . . the negative solution is extraneous

Then the length is 2·(11/2) -3 = 8.

The width of the rectangle is 5.5 yards; the length is 8 yards.

2 is the final ! : )

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05