You have a cone with a radius of 8 ft and a height of 10 ft. find the area of the triangle formed by a perpendicular cross-section through the cone’s center.

80ft²

Step-by-step explanation:

Given in the question,

radius of cone's base = 8ft

              cone's base = base of triangle

height of cone = 10 ft

height of cone = height of triangle

Area = 1/2(h)(b)

here h = height of triangle

        b = base of triangle

A = 1/2(8)(10)

A = 40ft²

Since the section is 2 similar triangles back to back around the vertical centre so the area cross sectional area of triangle form in the cone is 2(40)ft² = 80ft²

mean, 40.6

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb