Formulate the quadratic function that contains the points (-1,2), (0,-1) and (2,5).
1.) f(x) = 2x^2 + x + 1
2.) f(x) = 2x^2 - x - 1
3.) f(x) = 2x^2 - x + 2
4.) f(x) = 2x^2 - x - 2

option 2

2x²- x - 1

Step-by-step explanation:

We are given points: (-1,2), (0,-1) and (2,5)

Substitute each point one by one in the quadratic equation to check if the quadratic equation contains all points mention.

2) f(x) = 2x²- x - 1

   Point(-1,2)

   f(-1) = 2(-1)² -(-1) -1

   2 = 2 + 1 - 1

   2 = 2

  Point(0,-1)

   f(0) = 2(0)² -(0) -1

   -1 = 0 - 0 -1

   -1 = -1

  Point(2,5)

  f(2) = 2(2)² -(2) -1

  5 = 8 - 2 -1

  5 = 6 - 1

  5 = 5    

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.