Total crimes 21,790,654. roberry is 408, 016 and burglary is 2,050,992 what are their percent in crimes rounded to the nearest percent for each two crimes

Percent of Robbery

Percent of Robbery

Step-by-step explanation:

Given that total number of crimes = 21,790,654.

total number of Robbery = 408, 016 and

total number of Burglary = 2,050,992

Now we need to find about what are their percent in crimes rounded to the nearest percent for each two crimes.

So apply the percent formula

Then percent of Robbery

Then percent of Robbery

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.