Acountry’s population in 1993 was 94 million.
in 1999 it was 99 million l. estimate the population in 2005 using the exponential growth formula.

Step-by-step explanation:

A = Pe^rt

A = total

P = amount you start with

r = rate

t = time

Let's calculate the rate.

99000000 = 94000000e^r*6

Divide each side by 94m

99000000/94000000 = e^6r

Take the natural log of e of both sides.

ln(99000000/94000000) = 6r

Divide each side by 6.

(ln(99000000/94000000))/6 = r

Now we can find the population in 2005.

A = 94000000e^0.00863751131 * 12

A = 104265957

The population in 2005 is 104,265,957 people.

answer:   n ≤ -3 or n < -5

step-by-step explanation:

-5 + 2n ≥ -11

+5             +5

2n ≥ -6

2/2 ≤ -6/2

n ≤ -3

-6 - 10n > 44

+6           +6

-10n > 50

-10/-10 50/-10

n < -5

21/58.

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