Abeekeeper’s hives are making honey at a constant rate. the profit from honey can be represented by the equation

p(t)= -16t^2 + 2050t +150, where t is the time in days and p(t) is the profit the beekeeper receives. after how many days should she harvest her honey to maximize profit?

a: 4212100
b: 2050
c: 150
d: 64

Step-by-step explanation:

Hello

A beekeeper’s hives are making Honey at a constant rate. The profit from honey can be represented by the equation

P(t)= -16t^2 + 2050t +150, where t is the time in days and P(t) is the profit the beekeeper receives. After how many days should she harvest her honey to maximize profit?

A: 4212100

B: 2050

C: 150

D: 64

P(64)= -16(64)^2 + 2050(64) +150 = -16 * 4096 + 131200 + 150 = 65814

P(150)= -16(150)^2 + 2050(150) +150 = -16 * 22500 + 307500 + 150 = -52350

P(64)= -16(2050)^2 + 2050(2050) +150 = -16 * 4202500 + 4202500 + 150 = -63 037 350

The only is positif, it’s 64 days

step-by-step explanation:

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.