What are the points of discontinuity? are they removable? y = (x-5) / x^2 - 6x + 5

The points of discontinuity are: x=5 and x=1. The point of discontinuity x=5 can be removable.

Step-by-step explanation:

The points of discontinuity are those points where the function is not defined. To find such points, we should factorize the denominator of the function needs to be factorized.

Considering the quadratic equation of the form ax^2+bx+c =0, then using the quadratic (see attached image), where a=, b=- and c=5, we have that the roots are:

                                              x=5 and x=1.

If we simplify the fraction, by removing the term (x-5) from both the numerator and the denominator, we get: , so we removed the point of discontinuity x=5.

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step-by-step explanation:

(sorry i'm not typing it again just read the other two explanation sections i just typed it'll be the same.)