Solve the systems of equation by graphing (picture provided)

Option b

Step-by-step explanation:

The following system of linear equations is shown

These are two different slope lines.

We find the cut points of both lines with the axes.

Cut with the x axis. (y = 0)

Cut with the y axis. (x = 0)

...................................................................

Cut with the x axis. (y = 0)

Cut with the y axis. (x = 0)

The solution to this system will be a point for which it is fulfilled that:

In the image, different graphs with intersections are shown.

Locate among the options, one that shows the two lines of the system of equations according to their intersections with the x and y axes.

Option b is the only one that shows the graph of the lines

Then, The point of intersection of both lines in the graph is:

(-5, 13)

Therefore the solution of the system of equations is: (-5, 13)

You can verify this by replacing the point in the relationship

Equality is satisfied

Finally the answer is the option b

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step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb