Mr. jefferson has 20 students in his class. he wants to send 4 of these students to pick up books for the class. how many combinations of 4 students can he choose? 80 5 4845 116,280

4845 combinations

Step-by-step explanation:

Whenever there is a selection of some elements from a certain group, there are several ways to do so. There are different combinations from the group which can be selected. The concept of combination means that there are certain number of elements to be selected from the group and there is no importance given to the order of the selection. The total number of students are 20, and 4 out of them have to be selected. It can be clearly seen that the order of selection does not matter, therefore the formula to be used is:

Combinations = 20C4 = (20*19*18*17)/(4*3*2*1) = 4845.

So the correct answer is 4845 combinations!!!

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl